Discussion Question 5

ASA,

Discuss how we are to determine the slope of a graph. Also, what two forms of equations representing a graph did we learn in class on Friday? Is understanding slope important when using these forms? Why or why not? Lastly, what does the x-intercept and y-intercept tell us a about a graph?

Due Date: Monday, November 19, 2012 @ 11:59pm. 

Don't forget, the correct way to answer your discussion questions are in complete sentences in paragraph form. I did not take off points last discussion question, but I will in the future if you do not answer them in the correct format. 

Proportions Word Problem Video

ASA!

Here is a great video on how to word problems using proportions! Remember if your having trouble, practice, practice, practice! There are many great examples in the video.

Watch Below!

Discussion Question 4

ASA Everyone!

So,

Today we went over proportions. Define the word proportion(mathematics term).
Suppose it takes 48 slices of bean pie to feed Mr. Muhammad's 4th grade class of 20 students. How many slices of bean pie would be needed for 30 students?

Hint: make a proportion!


Due: Wednesday, November 14, 2012 @ 11:59 pm.

Final Exam Last Minute Notes

ASA!

Don't forget tomorrow is your Algebra II final!

We will start the final at 8:40am! Come prepared with your pencil and calculator!

Also, don't forget your warm-ups and your review packet. Your review packet is 15% of your final grade and for each warm-up brought tomorrow you will receive one extra credit point toward your final.


Study Hard!

Discussion Question 3

What is a linear equation? Is there one set way to solve a linear equation? Why or why not?

Due: Monday November 5, 2012 @ 11:59pm

Remember, always write your comments in complete sentences. Your comments should be at least 5 sentences long (a paragraph).

Video on How to Solve Linear Equations

Here's a helpful video on Linear Equations by Khan academy!

Watch!!

Homework Help- Linear Equations

ASA!

Having trouble with linear equations? Remember the goal is to get all variables on one said of the equal sign and get all numbers on the other side of the equal sign.

For example: Number 25 in your book work pg. 21

2z - 3 = 6z + 25

1. We notice that on each side of the equal sign there is a variable and a number ( 2z - 3, 6z + 25)
2. We need to move the numbers all on one side.
3. Lets move the 3 first. Since the three is subtracted we add it to both sides to get rid of it.

2z - 3 = 6z + 25
     +3         +3
---------------------
2z +0 = 6z + 28     or      2z = 6z + 28 ( I removed the zero)

4. But we are still not done. We need to get all the "like" terms on one side. Lets move the z's all to one side and keep the numbers on the other. In order to do that we must subtract 6z from both sides.

2z = 6z + 28
-6z   -6z
---------------------
-4z = 0 + 28      or    -4z = 28

5. Last step, solve for z. Since the -4 is multiplied by the z, divide -4 on both sides of the equal sign.

-4z = 28
----    ----
-4      -4

z = -7