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Wednesday, October 31, 2012

Homework Help- Linear Equations

ASA!

Having trouble with linear equations? Remember the goal is to get all variables on one said of the equal sign and get all numbers on the other side of the equal sign.

For example: Number 25 in your book work pg. 21

2z - 3 = 6z + 25

1. We notice that on each side of the equal sign there is a variable and a number ( 2z - 3, 6z + 25)
2. We need to move the numbers all on one side.
3. Lets move the 3 first. Since the three is subtracted we add it to both sides to get rid of it.

2z - 3 = 6z + 25
     +3         +3
---------------------
2z +0 = 6z + 28     or      2z = 6z + 28 ( I removed the zero)

4. But we are still not done. We need to get all the "like" terms on one side. Lets move the z's all to one side and keep the numbers on the other. In order to do that we must subtract 6z from both sides.

2z = 6z + 28
-6z   -6z
---------------------
-4z = 0 + 28      or    -4z = 28

5. Last step, solve for z. Since the -4 is multiplied by the z, divide -4 on both sides of the equal sign.

-4z = 28
----    ----
-4      -4

z = -7



1 comment:

  1. Thanks for the help sis ashley this example really helped me out with linear equation this math class went off to a rocky start insha allah it will get way better

    ReplyDelete